What is the answer to log_{2}(x+2)=-4 ?

The answer to log_{2}(x+2)=-4 is x=-31/16

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log_{2}(x+2)=-4

lo g_{2} (x + 2) = - 4

x = - \frac{31}{16}

Solution steps

lo g_{2} (x + 2) = - 4

Apply log rules

x + 2 = \frac{1}{16}

Solve

x + 2 = \frac{1}{16} : x = - \frac{31}{16}

x = - \frac{31}{16}

x, ln (x) = y t + c

lo g_{2} (x) + lo g_{2} (x + 3) = 2

lo g_{5} (a) = 3

lo g_{2} (x - 7) = 4 + lo g_{2} (x + 8)

x, z = ln (x + y)

What is the answer to log_{2}(x+2)=-4 ?
The answer to log_{2}(x+2)=-4 is x=-31/16
Solve for x: log_{2}(x+2)=-4
The solution is x=-31/16