What is the answer to log_{3}(2x^2+17x)=2 ?

The answer to log_{3}(2x^2+17x)=2 is x= 1/2 ,x=-9

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log_{3}(2x^2+17x)=2

lo g_{3} (2 x^{2} + 17 x) = 2

x = \frac{1}{2}, x = - 9

Decimal Notation

x = 0.5, x = - 9

Solution steps

lo g_{3} (2 x^{2} + 17 x) = 2

Apply log rules

2 x^{2} + 17 x = 9

Solve

2 x^{2} + 17 x = 9 : x = \frac{1}{2}, x = - 9

x = \frac{1}{2}, x = - 9

lo g_{10} (y + 21) + lo g_{10} (y) = 2

ln ((x - 2)^{2}) = 12

lo g_{2} (x^{2} - 1) = lo g_{2} (8)

lo g_{x} (243) = 2.5

lo g_{6} (2 x) = 3

What is the answer to log_{3}(2x^2+17x)=2 ?
The answer to log_{3}(2x^2+17x)=2 is x= 1/2 ,x=-9
Solve for x: log_{3}(2x^2+17x)=2
The solution is x= 1/2 ,x=-9