What is the answer to log_{2}(3x+1)=log_{2}(x+3) ?

The answer to log_{2}(3x+1)=log_{2}(x+3) is x=1

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log_{2}(3x+1)=log_{2}(x+3)

lo g_{2} (3 x + 1) = lo g_{2} (x + 3)

x = 1

Solution steps

lo g_{2} (3 x + 1) = lo g_{2} (x + 3)

Apply log rules

3 x + 1 = x + 3

Solve

3 x + 1 = x + 3 : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

2 lo g_{10} (x - 1) - lo g_{10} (x) = 0

lo g_{2} (4 x - 1) = 3

x, y = ln (x y)

ln (1 - 2 x) = 0.4

lo g_{10} (x^{3} + 2000) = 2

What is the answer to log_{2}(3x+1)=log_{2}(x+3) ?
The answer to log_{2}(3x+1)=log_{2}(x+3) is x=1
Solve for x: log_{2}(3x+1)=log_{2}(x+3)
The solution is x=1