What is the answer to log_{3}(2x-1)=-1 ?

The answer to log_{3}(2x-1)=-1 is x= 2/3

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log_{3}(2x-1)=-1

lo g_{3} (2 x - 1) = - 1

x = \frac{2}{3}

Solution steps

lo g_{3} (2 x - 1) = - 1

Apply log rules

2 x - 1 = \frac{1}{3}

Solve

2 x - 1 = \frac{1}{3} : x = \frac{2}{3}

x = \frac{2}{3}

lo g_{x} (3 - 2 x) = 2

lo g_{2} (5 x + 5) = 3

lo g_{3} (2 x + 7) = 2 + lo g_{3} (x)

(ln (x))^{4} - 3 (ln (x))^{2} - 4 = 0

40 = - 10 lo g_{10} ((1 - x)^{2})

What is the answer to log_{3}(2x-1)=-1 ?
The answer to log_{3}(2x-1)=-1 is x= 2/3
Solve for x: log_{3}(2x-1)=-1
The solution is x= 2/3