What is the answer to log_{10}(1-k)=-(0.3)/8 ?

The answer to log_{10}(1-k)=-(0.3)/8 is k=(-1+10^{3/80})/(10^{3/80)}

Solve for k: log_{10}(1-k)=-(0.3)/8

The solution is k=(-1+10^{3/80})/(10^{3/80)}

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lo g_{10} (1 - k) = - \frac{0.3}{8}

k = \frac{- 1 + 1 0 ^{\frac{3}{80}}}{1 0 ^{\frac{3}{80}}}

Decimal Notation

k = 0.08272 \dots

Solution steps

lo g_{10} (1 - k) = - \frac{0.3}{8}

Apply log rules

1 - k = \frac{1}{1 0 ^{\frac{0.3}{8}}}

Solve

1 - k = \frac{1}{1 0 ^{\frac{0.3}{8}}} : k = \frac{- 1 + 1 0 ^{\frac{3}{80}}}{1 0 ^{\frac{3}{80}}}

k = \frac{- 1 + 1 0 ^{\frac{3}{80}}}{1 0 ^{\frac{3}{80}}}

lo g_{b} (3) = 1

lo g_{16} (36) = 1 - lo g_{4} (x)

n - 8 lo g_{10} (n) = 0

x, lo g_{3} (x + 1) = 3

4 ln (- x) + 3 = 21

What is the answer to log_{10}(1-k)=-(0.3)/8 ?
The answer to log_{10}(1-k)=-(0.3)/8 is k=(-1+10^{3/80})/(10^{3/80)}
Solve for k: log_{10}(1-k)=-(0.3)/8
The solution is k=(-1+10^{3/80})/(10^{3/80)}