What is the answer to log_{2}(x-2)+2=log_{2}(32) ?

The answer to log_{2}(x-2)+2=log_{2}(32) is x=10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(x-2)+2=log_{2}(32)

lo g_{2} (x - 2) + 2 = lo g_{2} (32)

x = 10

Solution steps

lo g_{2} (x - 2) + 2 = lo g_{2} (32)

Move

2

to the right side

lo g_{2} (x - 2) = lo g_{2} (32) - 2

Apply log rules

x - 2 = 8

Solve

x - 2 = 8 : x = 10

x = 10

Verify Solutions:

x = 10

True

The solution is

x = 10

lo g_{0.3} (x) = 3

ln (x^{2} + 5 x) = 2 ln (x + 1)

lo g_{6} (x) + lo g_{6} (3) = 2

lo g_{10} (z - 3) = 2

lo g_{10} ((x + 1)^{3}) = 2

What is the answer to log_{2}(x-2)+2=log_{2}(32) ?
The answer to log_{2}(x-2)+2=log_{2}(32) is x=10
Solve for x: log_{2}(x-2)+2=log_{2}(32)
The solution is x=10