What is the answer to log_{x}(30-4x-x^2)=2 ?

The answer to log_{x}(30-4x-x^2)=2 is x=3

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log_{x}(30-4x-x^2)=2

lo g_{x} (30 - 4 x - x^{2}) = 2

x = 3

Solution steps

lo g_{x} (30 - 4 x - x^{2}) = 2

Apply log rules

\frac{ln ( 30 - 4 x - x ^{2} )}{ln ( x )} = 2

Multiply both sides by

ln (x)

\frac{ln ( 30 - 4 x - x ^{2} )}{ln ( x )} ln (x) = 2 ln (x)

Simplify

ln (30 - 4 x - x^{2}) = 2 ln (x)

Apply log rules

30 - 4 x - x^{2} = x^{2}

Solve

30 - 4 x - x^{2} = x^{2} : x = - 5, x = 3

x = - 5, x = 3

Verify Solutions:

x = - 5

False

, x = 3

True

The solution is

x = 3

x, lo g_{x} (y) = 2

ln (x) = 5.647091607

ln (2) - ln (2 - 5 x) = ln (64)

lo g_{6} (8) + lo g_{6} (x - 7) = 1

lo g_{10} (x^{2}) + 3 x = 1

What is the answer to log_{x}(30-4x-x^2)=2 ?
The answer to log_{x}(30-4x-x^2)=2 is x=3
Solve for x: log_{x}(30-4x-x^2)=2
The solution is x=3