What is the answer to solvefor x,log_{x}(y)=2 ?

The answer to solvefor x,log_{x}(y)=2 is x=e^{(ln(y))/2} {0 1}

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solvefor x,log_{x}(y)=2

solve for

x, lo g_{x} (y) = 2

x = e^{\frac{l n ( y )}{2}} {0 < y < 1 or y > 1}

Solution steps

lo g_{x} (y) = 2

Apply log rules

\frac{ln ( y )}{ln ( x )} = 2

Multiply both sides by

ln (x)

\frac{ln ( y )}{ln ( x )} ln (x) = 2 ln (x)

Simplify

ln (y) = 2 ln (x)

Switch sides

2 ln (x) = ln (y)

Divide both sides by

2

ln (x) = \frac{ln ( y )}{2}

Apply log rules

x = e^{\frac{l n ( y )}{2}}

Verify Solutions:

x = e^{\frac{l n ( y )}{2}} {0 < y < 1 or y > 1}

The solution is

x = e^{\frac{l n ( y )}{2}} {0 < y < 1 or y > 1}

ln (x) = 5.647091607

ln (2) - ln (2 - 5 x) = ln (64)

lo g_{6} (8) + lo g_{6} (x - 7) = 1

lo g_{10} (x^{2}) + 3 x = 1

u, lo g_{3} (3 u) = t

What is the answer to solvefor x,log_{x}(y)=2 ?
The answer to solvefor x,log_{x}(y)=2 is x=e^{(ln(y))/2} {0<y<1\lor y>1}