What is the answer to (log_{3}(x)-1)log_{3}(x)=0 ?

The answer to (log_{3}(x)-1)log_{3}(x)=0 is x=3,x=1

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(log_{3}(x)-1)log_{3}(x)=0

(lo g_{3} (x) - 1) lo g_{3} (x) = 0

x = 3, x = 1

Solution steps

(lo g_{3} (x) - 1) lo g_{3} (x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

lo g_{3} (x) - 1 = 0 or lo g_{3} (x) = 0

Solve

lo g_{3} (x) - 1 = 0 : x = 3

Solve

lo g_{3} (x) = 0 : x = 1

Verify Solutions:

x = 3

True

, x = 1

True

The solutions are

x = 3, x = 1

lo g_{10} (12 X) = \frac{4}{5}

ln (2 x) - 5 ln (x^{2}) = 0

1 - lo g_{10} (w - 7) = 0

lo g_{10} (x) 7 = - 2

2 = lo g_{e} (x)

What is the answer to (log_{3}(x)-1)log_{3}(x)=0 ?
The answer to (log_{3}(x)-1)log_{3}(x)=0 is x=3,x=1
Solve for x: (log_{3}(x)-1)log_{3}(x)=0
The solution is x=3,x=1