What is the answer to ln(x)=-0.432 ?

The answer to ln(x)=-0.432 is x= 1/(e^{0.432)}

Solve for x: ln(x)=-0.432

The solution is x= 1/(e^{0.432)}

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ln (x) = - 0.432

x = \frac{1}{e ^{0.432}}

Decimal

x = 0.64920 \dots

Solution steps

ln (x) = - 0.432

Apply log rules

x = \frac{1}{e ^{0.432}}

lo g_{5} (5^{x}) = lo g_{5} (1)

lo g_{10} (x) = - 2.22

lo g_{3} (x + 7) = 2 + lo g_{3} (x - 1)

lo g_{6} (8 x) - 3 lo g_{6} (5) = 0

2 ln (4 x) = - 2

What is the answer to ln(x)=-0.432 ?
The answer to ln(x)=-0.432 is x= 1/(e^{0.432)}
Solve for x: ln(x)=-0.432
The solution is x= 1/(e^{0.432)}