What are the solutions to the equation (3-2g)(7-g)=0 ?

The solutions to the equation (3-2g)(7-g)=0 are g= 3/2 ,g=7

Find the zeros of (3-2g)(7-g)=0

The zeros of (3-2g)(7-g)=0 are g= 3/2 ,g=7

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(3 - 2 g) (7 - g) = 0

g = \frac{3}{2}, g = 7

Decimal Notation

g = 1.5, g = 7

Solution steps

(3 - 2 g) (7 - g) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 - 2 g = 0 or 7 - g = 0

Solve

3 - 2 g = 0 : g = \frac{3}{2}

Solve

7 - g = 0 : g = 7

The solutions to the quadratic equation are:

g = \frac{3}{2}, g = 7

5 x^{2} - 4 x - 12 = 0

(e^{- \frac{x}{2}})^{2}

2 n^{2} - 4 n - 14 = 0

- 4 i^{2}

- 2 x + 1 = - x + 8

What are the solutions to the equation (3-2g)(7-g)=0 ?
The solutions to the equation (3-2g)(7-g)=0 are g= 3/2 ,g=7
Find the zeros of (3-2g)(7-g)=0
The zeros of (3-2g)(7-g)=0 are g= 3/2 ,g=7