What is the answer to 4-log_{2}(1-3x)=3 ?

The answer to 4-log_{2}(1-3x)=3 is x=-1/3

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4-log_{2}(1-3x)=3

4 - lo g_{2} (1 - 3 x) = 3

x = - \frac{1}{3}

Decimal Notation

x = - 0.33333 \dots

Solution steps

4 - lo g_{2} (1 - 3 x) = 3

Move

4

to the right side

- lo g_{2} (1 - 3 x) = - 1

Divide both sides by

- 1

lo g_{2} (1 - 3 x) = 1

Apply log rules

1 - 3 x = 2

Solve

1 - 3 x = 2 : x = - \frac{1}{3}

x = - \frac{1}{3}

Verify Solutions:

x = - \frac{1}{3}

True

The solution is

x = - \frac{1}{3}

2 x^{2} = \frac{x ^{2}}{ln ( x )}

ln (x^{2}) = 4 ln (x)

lo g_{100} (x) = \frac{3}{2}

0.21 = ln (y)

lo g_{4} (2 x + 5) - lo g_{4} (3 - x) = 2

What is the answer to 4-log_{2}(1-3x)=3 ?
The answer to 4-log_{2}(1-3x)=3 is x=-1/3
Solve for x: 4-log_{2}(1-3x)=3
The solution is x=-1/3