What is the answer to 7log_{4}(0.6x)=12 ?

The answer to 7log_{4}(0.6x)=12 is x=(20*4^{5/7})/3

Solve for x: 7log_{4}(0.6x)=12

The solution is x=(20*4^{5/7})/3

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7 lo g_{4} (0.6 x) = 12

x = \frac{20 \cdot 4 ^{\frac{5}{7}}}{3}

Decimal Notation

x = 17.94533 \dots

Solution steps

7 lo g_{4} (0.6 x) = 12

Divide both sides by

7

lo g_{4} (0.6 x) = \frac{12}{7}

Apply log rules

0.6 x = 4 \cdot 4^{\frac{5}{7}}

Solve

0.6 x = 4 \cdot 4^{\frac{5}{7}} : x = \frac{20 \cdot 4 ^{\frac{5}{7}}}{3}

x = \frac{20 \cdot 4 ^{\frac{5}{7}}}{3}

Verify Solutions:

x = \frac{20 \cdot 4 ^{\frac{5}{7}}}{3}

True

The solution is

x = \frac{20 \cdot 4 ^{\frac{5}{7}}}{3}

lo g_{7} (3 - 7 x) = 2

lo g_{2} (x^{2} - 3 x - 2) = 4

x - 3 + 2 ln (x) = 0

x, lo g_{10} (2 x + 1) = 2

lo g_{2} (x + 1) + lo g_{2} (x + 1) = 3

What is the answer to 7log_{4}(0.6x)=12 ?
The answer to 7log_{4}(0.6x)=12 is x=(20*4^{5/7})/3
Solve for x: 7log_{4}(0.6x)=12
The solution is x=(20*4^{5/7})/3