What is the answer to log_{x}(32)=-2 ?

The answer to log_{x}(32)=-2 is x= 1/(4sqrt(2))

Solve for x: log_{x}(32)=-2

The solution is x= 1/(4sqrt(2))

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lo g_{x} (32) = - 2

x = \frac{1}{4 2}

Decimal Notation

x = 0.17677 \dots

Solution steps

lo g_{x} (32) = - 2

Apply log rules

\frac{1}{lo g _{32} ( x )} = - 2

Multiply both sides by

lo g_{32} (x)

\frac{1}{lo g _{32} ( x )} lo g_{32} (x) = - 2 lo g_{32} (x)

Simplify

1 = - 2 lo g_{32} (x)

Switch sides

- 2 lo g_{32} (x) = 1

Divide both sides by

- 2

lo g_{32} (x) = - \frac{1}{2}

Apply log rules

x = \frac{1}{4 2}

Verify Solutions:

x = \frac{1}{4 2}

True

The solution is

x = \frac{1}{4 2}

ln (4 - 2 x) + ln (9 - 3 x) = 2 ln (x + 1)

4.9 = lo g_{10} (\frac{a}{a ^{0}})

lo g_{36} (N) = - \frac{3}{2}

lo g_{2} (5 x + 6) = 4

lo g_{10} (x - 1) = 2 lo g_{10} (x) - 1

What is the answer to log_{x}(32)=-2 ?
The answer to log_{x}(32)=-2 is x= 1/(4sqrt(2))
Solve for x: log_{x}(32)=-2
The solution is x= 1/(4sqrt(2))