What is the answer to ln(x+3)*ln(x-3)=0 ?

The answer to ln(x+3)*ln(x-3)=0 is x=4

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ln(x+3)*ln(x-3)=0

ln (x + 3) \cdot ln (x - 3) = 0

x = 4

Solution steps

ln (x + 3) ln (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

ln (x + 3) = 0 or ln (x - 3) = 0

Solve

ln (x + 3) = 0 : x = - 2

Solve

ln (x - 3) = 0 : x = 4

Verify Solutions:

x = - 2

False

, x = 4

True

The solution is

x = 4

lo g_{10} (5 x + 3) = lo g_{10} (12)

ln (3 x - 15) = 8

ln (1 - 4 k) = - 6 k

lo g_{10} (x + 8) + lo g_{10} (15) = 2

lo g_{8} (2 x^{2} - 6 x - 16) = 2

What is the answer to ln(x+3)*ln(x-3)=0 ?
The answer to ln(x+3)*ln(x-3)=0 is x=4
Solve for x: ln(x+3)*ln(x-3)=0
The solution is x=4