What is the answer to log_{10}(x+8)+log_{10}(15)=2 ?

The answer to log_{10}(x+8)+log_{10}(15)=2 is x=-4/3

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log_{10}(x+8)+log_{10}(15)=2

lo g_{10} (x + 8) + lo g_{10} (15) = 2

x = - \frac{4}{3}

Decimal

x = - 1.33333 \dots

Solution steps

lo g_{10} (x + 8) + lo g_{10} (15) = 2

Move

lo g_{10} (15)

to the right side

lo g_{10} (x + 8) = 2 - lo g_{10} (15)

Apply log rules

x + 8 = \frac{20}{3}

Solve

x + 8 = \frac{20}{3} : x = - \frac{4}{3}

x = - \frac{4}{3}

Verify Solutions:

x = - \frac{4}{3}

True

The solution is

x = - \frac{4}{3}

lo g_{8} (2 x^{2} - 6 x - 16) = 2

lo g_{5} (2 x + 1) = 1 - lo g_{5} (2)

lo g_{x} (8) = 4

x, lo g_{3} (m x) = c

2.53 = ln (\frac{X}{25})

What is the answer to log_{10}(x+8)+log_{10}(15)=2 ?
The answer to log_{10}(x+8)+log_{10}(15)=2 is x=-4/3
Solve for x: log_{10}(x+8)+log_{10}(15)=2
The solution is x=-4/3