What is the answer to log_{2}(log_{2}(x+1))=1 ?

The answer to log_{2}(log_{2}(x+1))=1 is x=3

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log_{2}(log_{2}(x+1))=1

lo g_{2} (lo g_{2} (x + 1)) = 1

x = 3

Solution steps

lo g_{2} (lo g_{2} (x + 1)) = 1

Apply log rules

x + 1 = 4

Solve

x + 1 = 4 : x = 3

x = 3

Verify Solutions:

x = 3

True

The solution is

x = 3

x, y^{4} = ln (x y)

ln (x^{2} - x) = ln (6)

ln (x + 1) x = 0

- 1 + lo g_{3} (- 5 x + x^{2} - 62) = 3

ln (t) = 1

What is the answer to log_{2}(log_{2}(x+1))=1 ?
The answer to log_{2}(log_{2}(x+1))=1 is x=3
Solve for x: log_{2}(log_{2}(x+1))=1
The solution is x=3