What is the answer to log_{4}(y)-log_{2}(y)=12 ?

The answer to log_{4}(y)-log_{2}(y)=12 is y= 1/16777216

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log_{4}(y)-log_{2}(y)=12

lo g_{4} (y) - lo g_{2} (y) = 12

y = \frac{1}{16777216}

Decimal Notation

y = 5.96046 E - 8

Solution steps

lo g_{4} (y) - lo g_{2} (y) = 12

Apply log rules

y = \frac{1}{16777216}

Verify Solutions:

y = \frac{1}{16777216}

True

The solution is

y = \frac{1}{16777216}

lo g_{y} (100) = lo g_{10} (y)

\frac{ln ( x + 3 )}{ln ( x + 1 )} = 2

ln (2) + ln (x) = 5

5 lo g_{4} (64 k) = 18

lo g_{5} (x) + 2 lo g_{x} (5) = 3

What is the answer to log_{4}(y)-log_{2}(y)=12 ?
The answer to log_{4}(y)-log_{2}(y)=12 is y= 1/16777216
Solve for y: log_{4}(y)-log_{2}(y)=12
The solution is y= 1/16777216