What is the answer to log_{56}(x^2-x)=1 ?

The answer to log_{56}(x^2-x)=1 is x=8,x=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{56}(x^2-x)=1

lo g_{56} (x^{2} - x) = 1

x = 8, x = - 7

Solution steps

lo g_{56} (x^{2} - x) = 1

Apply log rules

x^{2} - x = 56

Solve

x^{2} - x = 56 : x = 8, x = - 7

x = 8, x = - 7

2 lo g_{3} (x) - lo g_{3} (x + 4) = 2

lo g_{10} (x - 3) = 1

0.26 = ln (x)

ln (20 C) = ln (5)

x, ln ((x + 1)^{2}) = 2

What is the answer to log_{56}(x^2-x)=1 ?
The answer to log_{56}(x^2-x)=1 is x=8,x=-7
Solve for x: log_{56}(x^2-x)=1
The solution is x=8,x=-7