What is the answer to ln(x^2)=0.31 ?

The answer to ln(x^2)=0.31 is x=sqrt(e^{0.31)},x=-sqrt(e^{0.31)}

Solve for x: ln(x^2)=0.31

The solution is x=sqrt(e^{0.31)},x=-sqrt(e^{0.31)}

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ln (x^{2}) = 0.31

x = e^{0.31}, x = - e^{0.31}

Decimal Notation

x = 1.16765 \dots, x = - 1.16765 \dots

Solution steps

ln (x^{2}) = 0.31

Apply log rules

x^{2} = e^{0.31}

Solve

x^{2} = e^{0.31} : x = e^{0.31}, x = - e^{0.31}

x = e^{0.31}, x = - e^{0.31}

lo g_{2} ((r + 18)^{2}) = 4

x, lo g_{4} (x - 2 y) = 0

lo g_{10} (2 x) = 0.8821

ln (- x) = x

ln (3 x - 5) + ln (3 x - 7) = 3 ln (2)

What is the answer to ln(x^2)=0.31 ?
The answer to ln(x^2)=0.31 is x=sqrt(e^{0.31)},x=-sqrt(e^{0.31)}
Solve for x: ln(x^2)=0.31
The solution is x=sqrt(e^{0.31)},x=-sqrt(e^{0.31)}