What is the answer to log_{2}(x+6)+log_{2}(x+7)=1 ?

The answer to log_{2}(x+6)+log_{2}(x+7)=1 is x=-5

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log_{2}(x+6)+log_{2}(x+7)=1

lo g_{2} (x + 6) + lo g_{2} (x + 7) = 1

x = - 5

Solution steps

lo g_{2} (x + 6) + lo g_{2} (x + 7) = 1

Apply log rules

(x + 6) (x + 7) = 2

Solve

(x + 6) (x + 7) = 2 : x = - 5, x = - 8

x = - 5, x = - 8

Verify Solutions:

x = - 5

True

, x = - 8

False

The solution is

x = - 5

lo g_{2} (x - 5) + lo g_{2} (x - 5) = 2

lo g_{2} (n) = 4

ln (x) + ln (x + 2) = ln (15)

lo g_{4} (x) = 2 + lo g_{4} (2)

16.04 = 10 \cdot lo g_{10} (x)

What is the answer to log_{2}(x+6)+log_{2}(x+7)=1 ?
The answer to log_{2}(x+6)+log_{2}(x+7)=1 is x=-5
Solve for x: log_{2}(x+6)+log_{2}(x+7)=1
The solution is x=-5