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Popular >

solvefor x,ln(x)=y^2+c

Solution

solve for

x, ln (x) = y^{2} + c

Solution

x = e^{y^{2} + c}

Solution steps

ln (x) = y^{2} + c

Apply log rules

x = e^{y^{2} + c}

Popular Examples

3 ln (x) + 2 = 0

log_{\sqrt[3]{n}}(n)=3

log_{2}(x)+1-log_{2}(x)-4=3

lo g_{2} (x) + 1 - lo g_{2} (x) - 4 = 3

log_{7}(x+4)-log_{7}(x-2)=1

lo g_{7} (x + 4) - lo g_{7} (x - 2) = 1

0 = 2 lo g_{10} (x)

Frequently Asked Questions (FAQ)

What is the answer to solvefor x,ln(x)=y^2+c ?
The answer to solvefor x,ln(x)=y^2+c is x=e^{y^2+c}