What is the answer to log_{2}(x)+1-log_{2}(x)-4=3 ?

The answer to log_{2}(x)+1-log_{2}(x)-4=3 is No Solution for x\in\mathbb{R}

Solve for x: log_{2}(x)+1-log_{2}(x)-4=3

The solution is No Solution for x\in\mathbb{R}

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lo g_{2} (x) + 1 - lo g_{2} (x) - 4 = 3

No Solution for x \in R

Solution steps

lo g_{2} (x) + 1 - lo g_{2} (x) - 4 = 3

Group like terms

lo g_{2} (x) - lo g_{2} (x) + 1 - 4 = 3

Add similar elements:

lo g_{2} (x) - lo g_{2} (x) = 0

1 - 4 = 3

Subtract the numbers:

1 - 4 = - 3

- 3 = 3

The sides are not equal

No Solution for x \in R

lo g_{7} (x + 4) - lo g_{7} (x - 2) = 1

0 = 2 lo g_{10} (x)

ln (x^{2} - 5 x - 1) - ln (3 - 2 x) = 0

ln (\frac{x}{x ^{2} + 1}) = 1

lo g_{2} (x) + 3 lo g_{10} (x) + 2 = 0

What is the answer to log_{2}(x)+1-log_{2}(x)-4=3 ?
The answer to log_{2}(x)+1-log_{2}(x)-4=3 is No Solution for x\in\mathbb{R}
Solve for x: log_{2}(x)+1-log_{2}(x)-4=3
The solution is No Solution for x\in\mathbb{R}