What is the answer to log_{2}(x+7)=log_{2}(x+4)+2 ?

The answer to log_{2}(x+7)=log_{2}(x+4)+2 is x=-3

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log_{2}(x+7)=log_{2}(x+4)+2

lo g_{2} (x + 7) = lo g_{2} (x + 4) + 2

x = - 3

Solution steps

lo g_{2} (x + 7) = lo g_{2} (x + 4) + 2

Apply log rules

x + 7 = (x + 4) \cdot 4

Solve

x + 7 = (x + 4) \cdot 4 : x = - 3

x = - 3

Verify Solutions:

x = - 3

True

The solution is

x = - 3

lo g_{2} (x + 1) + lo g_{2} (x + 7) = 3

lo g_{5} (7 - x) = 2

2 = lo g_{3} (x)

lo g_{4} (\frac{x}{2}) = 2

lo g_{2} (x) - lo g_{2} (x - 3) - 2 = 0

What is the answer to log_{2}(x+7)=log_{2}(x+4)+2 ?
The answer to log_{2}(x+7)=log_{2}(x+4)+2 is x=-3
Solve for x: log_{2}(x+7)=log_{2}(x+4)+2
The solution is x=-3