What is the answer to log_{2}(x)-log_{2}(x-3)-2=0 ?

The answer to log_{2}(x)-log_{2}(x-3)-2=0 is x=4

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log_{2}(x)-log_{2}(x-3)-2=0

lo g_{2} (x) - lo g_{2} (x - 3) - 2 = 0

x = 4

Solution steps

lo g_{2} (x) - lo g_{2} (x - 3) - 2 = 0

Add

lo g_{2} (x - 3)

to both sides

lo g_{2} (x) - lo g_{2} (x - 3) - 2 + lo g_{2} (x - 3) = 0 + lo g_{2} (x - 3)

Simplify

lo g_{2} (x) - 2 = lo g_{2} (x - 3)

Apply log rules

x = (x - 3) \cdot 4

Solve

x = (x - 3) \cdot 4 : x = 4

x = 4

Verify Solutions:

x = 4

True

The solution is

x = 4

y, x = 1 - ln (y - 2)

ln (2 x + 1) - ln (x) = 2 ln (3)

lo g_{10} (25) = 2 lo g_{10} (x)

3 lo g_{2} (3 x + 1) = 6

(ln (x))^{2} = 4

What is the answer to log_{2}(x)-log_{2}(x-3)-2=0 ?
The answer to log_{2}(x)-log_{2}(x-3)-2=0 is x=4
Solve for x: log_{2}(x)-log_{2}(x-3)-2=0
The solution is x=4