What is the answer to log_{5}(x)-log_{25}(x+6)=0 ?

The answer to log_{5}(x)-log_{25}(x+6)=0 is x=3

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log_{5}(x)-log_{25}(x+6)=0

lo g_{5} (x) - lo g_{25} (x + 6) = 0

x = 3

Solution steps

lo g_{5} (x) - lo g_{25} (x + 6) = 0

Apply log rules

x^{2} = x + 6

Solve

x^{2} = x + 6 : x = 3, x = - 2

x = 3, x = - 2

Verify Solutions:

x = 3

True

, x = - 2

False

The solution is

x = 3

lo g_{x} (512) = 9

ln (15) = ln (- n) - n ln (1.1)

lo g_{2} (x + 7) + lo g_{2} (x - 7) = 5

5 ln (3 x - 4) = 30

3^{l o g_{3} (3 x + 4)} = 3 x

What is the answer to log_{5}(x)-log_{25}(x+6)=0 ?
The answer to log_{5}(x)-log_{25}(x+6)=0 is x=3
Solve for x: log_{5}(x)-log_{25}(x+6)=0
The solution is x=3