What is the answer to log_{5}(5^x-20)=3-x ?

The answer to log_{5}(5^x-20)=3-x is x=2

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log_{5}(5^x-20)=3-x

lo g_{5} (5^{x} - 20) = 3 - x

x = 2

Solution steps

lo g_{5} (5^{x} - 20) = 3 - x

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

5^{l o g_{5} (5^{x} - 20)} = 5^{3 - x}

Simplify

5^{l o g_{5} (5^{x} - 20)} : 5^{x} - 20

5^{x} - 20 = 5^{3 - x}

Solve

5^{x} - 20 = 5^{3 - x} : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

2 lo g_{2} (x) = lo g_{2} (x + 12) + 1

v, ln (p) + R ln (v) = C

lo g_{y} (125) = 3

x, ln (x^{2} - y) = 0

2 lo g_{3} (- x + 1) = 6

What is the answer to log_{5}(5^x-20)=3-x ?
The answer to log_{5}(5^x-20)=3-x is x=2
Solve for x: log_{5}(5^x-20)=3-x
The solution is x=2