What is the answer to 2log_{2}(x)=log_{2}(x+12)+1 ?

The answer to 2log_{2}(x)=log_{2}(x+12)+1 is x=6

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2log_{2}(x)=log_{2}(x+12)+1

2 lo g_{2} (x) = lo g_{2} (x + 12) + 1

x = 6

Solution steps

2 lo g_{2} (x) = lo g_{2} (x + 12) + 1

Apply log rules

x^{2} = (x + 12) \cdot 2

Solve

x^{2} = (x + 12) \cdot 2 : x = 6, x = - 4

x = 6, x = - 4

Verify Solutions:

x = 6

True

, x = - 4

False

The solution is

x = 6

v, ln (p) + R ln (v) = C

lo g_{y} (125) = 3

x, ln (x^{2} - y) = 0

2 lo g_{3} (- x + 1) = 6

lo g_{10} (x + 1) = lo g_{10} (1 - x)

What is the answer to 2log_{2}(x)=log_{2}(x+12)+1 ?
The answer to 2log_{2}(x)=log_{2}(x+12)+1 is x=6
Solve for x: 2log_{2}(x)=log_{2}(x+12)+1
The solution is x=6