What is the answer to log_{10}(x+1)=log_{10}(1-x) ?

The answer to log_{10}(x+1)=log_{10}(1-x) is x=0

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log_{10}(x+1)=log_{10}(1-x)

lo g_{10} (x + 1) = lo g_{10} (1 - x)

x = 0

Solution steps

lo g_{10} (x + 1) = lo g_{10} (1 - x)

Apply log rules

x + 1 = 1 - x

Solve

x + 1 = 1 - x : x = 0

x = 0

Verify Solutions:

x = 0

True

The solution is

x = 0

lo g_{10} (x) (81) = 4

3 ln (6 x) = - 3

a, lo g_{10} (a^{2} b) = 1

lo g_{3} (- 4 x + 7) = 3

ln (x) = 1.5017800000000 \dots

What is the answer to log_{10}(x+1)=log_{10}(1-x) ?
The answer to log_{10}(x+1)=log_{10}(1-x) is x=0
Solve for x: log_{10}(x+1)=log_{10}(1-x)
The solution is x=0