What is the answer to 4log_{x}(2)-log_{2}(x)=3 ?

The answer to 4log_{x}(2)-log_{2}(x)=3 is x= 1/16 ,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4log_{x}(2)-log_{2}(x)=3

4 lo g_{x} (2) - lo g_{2} (x) = 3

x = \frac{1}{16}, x = 2

Solution steps

4 lo g_{x} (2) - lo g_{2} (x) = 3

Apply log rules

\frac{4}{lo g _{2} ( x )} - lo g_{2} (x) = 3

Rewrite the equation with

lo g_{2} (x) = u

\frac{4}{u} - u = 3

Solve

\frac{4}{u} - u = 3 : u = - 4, u = 1

u = - 4, u = 1

Substitute back

u = lo g_{2} (x),

solve for

x

Solve

lo g_{2} (x) = - 4 : x = \frac{1}{16}

Solve

lo g_{2} (x) = 1 : x = 2

x = \frac{1}{16}, x = 2

Verify Solutions:

x = \frac{1}{16}

True

, x = 2

True

The solutions are

x = \frac{1}{16}, x = 2

lo g_{7} (2 x) + lo g_{7} (2) = 5

2 ln (x - 1) + ln (x + 7) = 3 ln (x)

lo g_{4} (\frac{1}{2} x + 1) = 3.2

lo g_{10} (x) = 5.48

lo g_{3} (x^{3}) - lo g_{3} (9 x) = 2

What is the answer to 4log_{x}(2)-log_{2}(x)=3 ?
The answer to 4log_{x}(2)-log_{2}(x)=3 is x= 1/16 ,x=2
Solve for x: 4log_{x}(2)-log_{2}(x)=3
The solution is x= 1/16 ,x=2