What are the solutions to the equation 5c^2+5c=36 ?

The solutions to the equation 5c^2+5c=36 are c=(-5+sqrt(745))/(10),c=(-5-sqrt(745))/(10)

Find the zeros of 5c^2+5c=36

The zeros of 5c^2+5c=36 are c=(-5+sqrt(745))/(10),c=(-5-sqrt(745))/(10)

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5 c^{2} + 5 c = 36

c = \frac{- 5 + 745}{10}, c = \frac{- 5 - 745}{10}

Decimal Notation

c = 2.22946 \dots, c = - 3.22946 \dots

Solution steps

5 c^{2} + 5 c = 36

Move

36

to the left side

5 c^{2} + 5 c - 36 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 5 ( - 36 )}{2 \cdot 5}

5^{2} - 4 \cdot 5 (- 36) = 745

c_{1, 2} = \frac{- 5 \pm 745}{2 \cdot 5}

Separate the solutions

c_{1} = \frac{- 5 + 745}{2 \cdot 5}, c_{2} = \frac{- 5 - 745}{2 \cdot 5}

c = \frac{- 5 + 745}{2 \cdot 5} : \frac{- 5 + 745}{10}

c = \frac{- 5 - 745}{2 \cdot 5} : \frac{- 5 - 745}{10}

The solutions to the quadratic equation are:

c = \frac{- 5 + 745}{10}, c = \frac{- 5 - 745}{10}

j^{2} - 6 j - 7

\frac{4 ( x - y )}{x - y}

x^{3} - 13 x^{2} + 47 x - 35

- 2 x^{2} = - 128

3 (x + 2)^{2} = 54

What are the solutions to the equation 5c^2+5c=36 ?
The solutions to the equation 5c^2+5c=36 are c=(-5+sqrt(745))/(10),c=(-5-sqrt(745))/(10)
Find the zeros of 5c^2+5c=36
The zeros of 5c^2+5c=36 are c=(-5+sqrt(745))/(10),c=(-5-sqrt(745))/(10)