What is the answer to 0=log_{10}((T-22)/(75)) ?

The answer to 0=log_{10}((T-22)/(75)) is T=97

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0=log_{10}((T-22)/(75))

0 = lo g_{10} (\frac{T - 22}{75})

T = 97

Solution steps

0 = lo g_{10} (\frac{T - 22}{75})

Apply log rules

1 0^{0} = \frac{T - 22}{75}

Multiply both sides by

75

1 0^{0} \cdot 75 = \frac{T - 22}{75} \cdot 75

Simplify

75 = T - 22

Solve

75 = T - 22 : T = 97

T = 97

Verify Solutions:

T = 97

True

The solution is

T = 97

3 lo g_{2} (x) = 9

3 lo g_{4} (4 n - 5) + 4 = 7

1.3 = lo g_{10} (x)

lo g_{10} (\frac{1}{x}) = 1.62

lo g_{x - 1} (6 x - 14) = 2

What is the answer to 0=log_{10}((T-22)/(75)) ?
The answer to 0=log_{10}((T-22)/(75)) is T=97
Solve for T: 0=log_{10}((T-22)/(75))
The solution is T=97