What is the answer to 3log_{4}(4n-5)+4=7 ?

The answer to 3log_{4}(4n-5)+4=7 is n= 9/4

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3log_{4}(4n-5)+4=7

3 lo g_{4} (4 n - 5) + 4 = 7

n = \frac{9}{4}

Decimal Notation

n = 2.25

Solution steps

3 lo g_{4} (4 n - 5) + 4 = 7

Move

4

to the right side

3 lo g_{4} (4 n - 5) = 3

Divide both sides by

3

lo g_{4} (4 n - 5) = 1

Apply log rules

4 n - 5 = 4

Solve

4 n - 5 = 4 : n = \frac{9}{4}

n = \frac{9}{4}

Verify Solutions:

n = \frac{9}{4}

True

The solution is

n = \frac{9}{4}

1.3 = lo g_{10} (x)

lo g_{10} (\frac{1}{x}) = 1.62

lo g_{x - 1} (6 x - 14) = 2

lo g_{5} (2 x) + lo g_{5} (5) = 4

ln (x - 4) + ln (x + 1) = ln (x - 8)

What is the answer to 3log_{4}(4n-5)+4=7 ?
The answer to 3log_{4}(4n-5)+4=7 is n= 9/4
Solve for n: 3log_{4}(4n-5)+4=7
The solution is n= 9/4