What is the answer to log_{3}(x^2+7x+9)=2 ?

The answer to log_{3}(x^2+7x+9)=2 is x=0,x=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{3}(x^2+7x+9)=2

lo g_{3} (x^{2} + 7 x + 9) = 2

x = 0, x = - 7

Solution steps

lo g_{3} (x^{2} + 7 x + 9) = 2

Apply log rules

x^{2} + 7 x + 9 = 9

Solve

x^{2} + 7 x + 9 = 9 : x = 0, x = - 7

x = 0, x = - 7

lo g_{3} (x + 5) + lo g_{3} (x - 7) = 2

lo g_{e} (2 - 3 x) = 0

lo g_{9} (x^{9}) = 9

20 \cdot lo g_{10} (x^{2} - 15) = 0

y, x = lo g_{4} (y)

What is the answer to log_{3}(x^2+7x+9)=2 ?
The answer to log_{3}(x^2+7x+9)=2 is x=0,x=-7
Solve for x: log_{3}(x^2+7x+9)=2
The solution is x=0,x=-7