What is the answer to log_{4}((x-2)/(2x+3))=0 ?

The answer to log_{4}((x-2)/(2x+3))=0 is x=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{4}((x-2)/(2x+3))=0

lo g_{4} (\frac{x - 2}{2 x + 3}) = 0

x = - 5

Solution steps

lo g_{4} (\frac{x - 2}{2 x + 3}) = 0

Apply log rules

\frac{x - 2}{2 x + 3} = 4^{0}

Multiply both sides by

2 x + 3

\frac{x - 2}{2 x + 3} (2 x + 3) = 4^{0} (2 x + 3)

Simplify

x - 2 = 2 x + 3

Solve

x - 2 = 2 x + 3 : x = - 5

x = - 5

Verify Solutions:

x = - 5

True

The solution is

x = - 5

lo g_{10} (x) + lo g_{10} (80) = 3

ln (x^{- 1}) = 3

x, ln (x) + ln (x) = 0

ln (3 x) = x

lo g_{x + 6} (2 x^{2} - 4 x) = 2

What is the answer to log_{4}((x-2)/(2x+3))=0 ?
The answer to log_{4}((x-2)/(2x+3))=0 is x=-5
Solve for x: log_{4}((x-2)/(2x+3))=0
The solution is x=-5