What is the answer to 2log_{10}(x)+log_{10}(4)=2 ?

The answer to 2log_{10}(x)+log_{10}(4)=2 is x=10^{(2-2log_{10}(2))/2}

Solve for x: 2log_{10}(x)+log_{10}(4)=2

The solution is x=10^{(2-2log_{10}(2))/2}

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2 lo g_{10} (x) + lo g_{10} (4) = 2

x = 1 0^{\frac{2 - 2 l o g _{10} ( 2 )}{2}}

Solution steps

2 lo g_{10} (x) + lo g_{10} (4) = 2

Move

lo g_{10} (4)

to the right side

2 lo g_{10} (x) = 2 - lo g_{10} (4)

Divide both sides by

2

lo g_{10} (x) = \frac{2 - lo g _{10} ( 4 )}{2}

Apply log rules

x = 1 0^{\frac{2 - 2 l o g _{10} ( 2 )}{2}}

Verify Solutions:

x = 1 0^{\frac{2 - 2 l o g _{10} ( 2 )}{2}}

True

The solution is

x = 1 0^{\frac{2 - 2 l o g _{10} ( 2 )}{2}}

- 2 ln (x) - 3 = 0

lo g_{2} (2 x + 1) = - 3

x, ln (x) = 1

ln (y^{2}) = ln (y + 3) + 2

x, y = ln (3 x)

What is the answer to 2log_{10}(x)+log_{10}(4)=2 ?
The answer to 2log_{10}(x)+log_{10}(4)=2 is x=10^{(2-2log_{10}(2))/2}
Solve for x: 2log_{10}(x)+log_{10}(4)=2
The solution is x=10^{(2-2log_{10}(2))/2}