What is the answer to ln(x+63)-ln(4-3x)=6ln(2) ?

The answer to ln(x+63)-ln(4-3x)=6ln(2) is x=1

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ln(x+63)-ln(4-3x)=6ln(2)

ln (x + 63) - ln (4 - 3 x) = 6 ln (2)

x = 1

Solution steps

ln (x + 63) - ln (4 - 3 x) = 6 ln (2)

Add

ln (4 - 3 x)

to both sides

ln (x + 63) - ln (4 - 3 x) + ln (4 - 3 x) = 6 ln (2) + ln (4 - 3 x)

Simplify

ln (x + 63) = 6 ln (2) + ln (4 - 3 x)

Apply log rules

x + 63 = 64 (4 - 3 x)

Solve

x + 63 = 64 (4 - 3 x) : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

ln (8) - ln (5 x - 10) = 1

ln (x + 1) - ln (x - 2) = ln (x)

lo g_{2} (x - 6) - lo g_{2} (x + 2) = 4

lo g_{10} (x) (9) = 2

2 lo g_{10} (x + 3) = 2 x + 3

What is the answer to ln(x+63)-ln(4-3x)=6ln(2) ?
The answer to ln(x+63)-ln(4-3x)=6ln(2) is x=1
Solve for x: ln(x+63)-ln(4-3x)=6ln(2)
The solution is x=1