What is the answer to log_{2}(x-6)-log_{2}(x+2)=4 ?

The answer to log_{2}(x-6)-log_{2}(x+2)=4 is No Solution for x\in\mathbb{R}

Solve for x: log_{2}(x-6)-log_{2}(x+2)=4

The solution is No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{2} (x - 6) - lo g_{2} (x + 2) = 4

No Solution for x \in R

Solution steps

lo g_{2} (x - 6) - lo g_{2} (x + 2) = 4

Add

lo g_{2} (x + 2)

to both sides

lo g_{2} (x - 6) - lo g_{2} (x + 2) + lo g_{2} (x + 2) = 4 + lo g_{2} (x + 2)

Simplify

lo g_{2} (x - 6) = 4 + lo g_{2} (x + 2)

Apply log rules

x - 6 = 16 (x + 2)

Solve

x - 6 = 16 (x + 2) : x = - \frac{38}{15}

x = - \frac{38}{15}

Verify Solutions:

x = - \frac{38}{15}

False

The solution is

No Solution for x \in R

lo g_{10} (x) (9) = 2

2 lo g_{10} (x + 3) = 2 x + 3

lo g_{10} (x) + lo g_{10} (x + 4) = - 1

lo g_{125} (x) - lo g_{5} (x) = - 2

20 \cdot lo g_{10} (x) = 100

What is the answer to log_{2}(x-6)-log_{2}(x+2)=4 ?
The answer to log_{2}(x-6)-log_{2}(x+2)=4 is No Solution for x\in\mathbb{R}
Solve for x: log_{2}(x-6)-log_{2}(x+2)=4
The solution is No Solution for x\in\mathbb{R}