What is the answer to log_{10}(x)+log_{10}(x+4)=-1 ?

The answer to log_{10}(x)+log_{10}(x+4)=-1 is x=(-20+sqrt(410))/(10)

Solve for x: log_{10}(x)+log_{10}(x+4)=-1

The solution is x=(-20+sqrt(410))/(10)

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lo g_{10} (x) + lo g_{10} (x + 4) = - 1

x = \frac{- 20 + 410}{10}

Solution steps

lo g_{10} (x) + lo g_{10} (x + 4) = - 1

Apply log rules

x (x + 4) = \frac{1}{10}

Solve

x (x + 4) = \frac{1}{10} : x = \frac{- 20 + 410}{10}, x = - \frac{20 + 410}{10}

x = \frac{- 20 + 410}{10}, x = - \frac{20 + 410}{10}

Verify Solutions:

x = \frac{- 20 + 410}{10}

True

, x = - \frac{20 + 410}{10}

False

The solution is

x = \frac{- 20 + 410}{10}

lo g_{125} (x) - lo g_{5} (x) = - 2

20 \cdot lo g_{10} (x) = 100

lo g_{2} (x) \cdot lo g_{2} (x) = 9

lo g_{3} (x) - lo g_{9} (x + 42) = 0

lo g_{x} (121) = 2

What is the answer to log_{10}(x)+log_{10}(x+4)=-1 ?
The answer to log_{10}(x)+log_{10}(x+4)=-1 is x=(-20+sqrt(410))/(10)
Solve for x: log_{10}(x)+log_{10}(x+4)=-1
The solution is x=(-20+sqrt(410))/(10)