What is the answer to log_{3}(x)-log_{9}(x+42)=0 ?

The answer to log_{3}(x)-log_{9}(x+42)=0 is x=7

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log_{3}(x)-log_{9}(x+42)=0

lo g_{3} (x) - lo g_{9} (x + 42) = 0

x = 7

Solution steps

lo g_{3} (x) - lo g_{9} (x + 42) = 0

Apply log rules

x^{2} = x + 42

Solve

x^{2} = x + 42 : x = 7, x = - 6

x = 7, x = - 6

Verify Solutions:

x = 7

True

, x = - 6

False

The solution is

x = 7

lo g_{x} (121) = 2

lo g_{3 x} (18) = lo g_{4} (8)

lo g_{x} (8) = 3

ln (7 + 2 x) = ln (1 + 4 x)

lo g_{3} (x - 5) - lo g_{3} (x - 1) = 2

What is the answer to log_{3}(x)-log_{9}(x+42)=0 ?
The answer to log_{3}(x)-log_{9}(x+42)=0 is x=7
Solve for x: log_{3}(x)-log_{9}(x+42)=0
The solution is x=7