What is the answer to log_{3}(x-5)-log_{3}(x-1)=2 ?

The answer to log_{3}(x-5)-log_{3}(x-1)=2 is No Solution for x\in\mathbb{R}

Solve for x: log_{3}(x-5)-log_{3}(x-1)=2

The solution is No Solution for x\in\mathbb{R}

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lo g_{3} (x - 5) - lo g_{3} (x - 1) = 2

No Solution for x \in R

Solution steps

lo g_{3} (x - 5) - lo g_{3} (x - 1) = 2

Add

lo g_{3} (x - 1)

to both sides

lo g_{3} (x - 5) - lo g_{3} (x - 1) + lo g_{3} (x - 1) = 2 + lo g_{3} (x - 1)

Simplify

lo g_{3} (x - 5) = 2 + lo g_{3} (x - 1)

Apply log rules

x - 5 = 9 (x - 1)

Solve

x - 5 = 9 (x - 1) : x = \frac{1}{2}

x = \frac{1}{2}

Verify Solutions:

x = \frac{1}{2}

False

The solution is

No Solution for x \in R

lo g_{10} (5 x) + lo g_{10} (x + 5) = 1

ln (9 x + e) = 7

1 - lo g_{3} (8 x + 1) = 5

2 ln (5) + ln (x) - ln (4) = 3

ln (x + 11) + ln (x - 5) = 2 ln (x)

What is the answer to log_{3}(x-5)-log_{3}(x-1)=2 ?
The answer to log_{3}(x-5)-log_{3}(x-1)=2 is No Solution for x\in\mathbb{R}
Solve for x: log_{3}(x-5)-log_{3}(x-1)=2
The solution is No Solution for x\in\mathbb{R}