What is the answer to log_{10}(x^2)= 1/4 ?

The answer to log_{10}(x^2)= 1/4 is x=sqrt(\sqrt[4]{10)},x=-sqrt(\sqrt[4]{10)}

Solve for x: log_{10}(x^2)= 1/4

The solution is x=sqrt(\sqrt[4]{10)},x=-sqrt(\sqrt[4]{10)}

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lo g_{10} (x^{2}) = \frac{1}{4}

Solution steps

lo g_{10} (x^{2}) = \frac{1}{4}

Apply log rules

Solve

2 ln (2) = ln (4 - 8 + C)

lo g_{4} (2 x + 9) = 3

3 ln (x) + 2 ln (x^{2}) = 6

lo g_{4} (x^{2} + 2 x + 1) = 2

2^{l o g_{2} (x)} = x

What is the answer to log_{10}(x^2)= 1/4 ?
The answer to log_{10}(x^2)= 1/4 is x=sqrt(\sqrt[4]{10)},x=-sqrt(\sqrt[4]{10)}
Solve for x: log_{10}(x^2)= 1/4
The solution is x=sqrt(\sqrt[4]{10)},x=-sqrt(\sqrt[4]{10)}