What is the answer to ln(x)+log_{10}(x)=1 ?

The answer to ln(x)+log_{10}(x)=1 is x=10^{(log_{10}(e))/(1+log_{10)(e)}}

Solve for x: ln(x)+log_{10}(x)=1

The solution is x=10^{(log_{10}(e))/(1+log_{10)(e)}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ln (x) + lo g_{10} (x) = 1

x = 1 0^{\frac{l o g _{10} ( e )}{1 + l o g _{10} ( e )}}

Solution steps

ln (x) + lo g_{10} (x) = 1

Apply log rules

x = 1 0^{\frac{l o g _{10} ( e )}{1 + l o g _{10} ( e )}}

Verify Solutions:

x = 1 0^{\frac{l o g _{10} ( e )}{1 + l o g _{10} ( e )}}

True

The solution is

x = 1 0^{\frac{l o g _{10} ( e )}{1 + l o g _{10} ( e )}}

ln (x - 2) = ln (3) - ln (x)

lo g_{10} (x) = 1307

x, ln (x + y) - ln (x - y) = 4

ln (x) = 3.39

ln (x) = 3.49

What is the answer to ln(x)+log_{10}(x)=1 ?
The answer to ln(x)+log_{10}(x)=1 is x=10^{(log_{10}(e))/(1+log_{10)(e)}}
Solve for x: ln(x)+log_{10}(x)=1
The solution is x=10^{(log_{10}(e))/(1+log_{10)(e)}}