What is the answer to solvefor x,ln(x+y)-ln(x-y)=4 ?

The answer to solvefor x,ln(x+y)-ln(x-y)=4 is x=(-e^4y-y)/(1-e^4) {y>0}

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solvefor x,ln(x+y)-ln(x-y)=4

solve for

x, ln (x + y) - ln (x - y) = 4

x = \frac{- e ^{4} y - y}{1 - e ^{4}} {y > 0}

Solution steps

ln (x + y) - ln (x - y) = 4

Add

ln (x - y)

to both sides

ln (x + y) - ln (x - y) + ln (x - y) = 4 + ln (x - y)

Simplify

ln (x + y) = 4 + ln (x - y)

Apply log rules

x + y = e^{4} (x - y)

Solve

x + y = e^{4} (x - y) : x = \frac{- e ^{4} y - y}{1 - e ^{4}}

x = \frac{- e ^{4} y - y}{1 - e ^{4}}

Verify Solutions:

x = \frac{- e ^{4} y - y}{1 - e ^{4}} {y > 0}

The solution is

x = \frac{- e ^{4} y - y}{1 - e ^{4}} {y > 0}

ln (x) = 3.39

ln (x) = 3.49

ln (x) = 3.61

lo g_{2} (x + 7) = 2 + lo g_{2} (x - 11)

ln (5 - 2 x) + ln (9) = 4

What is the answer to solvefor x,ln(x+y)-ln(x-y)=4 ?
The answer to solvefor x,ln(x+y)-ln(x-y)=4 is x=(-e^4y-y)/(1-e^4) {y>0}