What is the answer to ln(5-2x)+ln(9)=4 ?

The answer to ln(5-2x)+ln(9)=4 is x=-(e^4-45)/(18)

Solve for x: ln(5-2x)+ln(9)=4

The solution is x=-(e^4-45)/(18)

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ln (5 - 2 x) + ln (9) = 4

x = - \frac{e ^{4} - 45}{18}

Decimal Notation

x = - 0.53323 \dots

Solution steps

ln (5 - 2 x) + ln (9) = 4

Move

ln (9)

to the right side

ln (5 - 2 x) = 4 - ln (9)

Apply log rules

5 - 2 x = \frac{e ^{4}}{9}

Solve

5 - 2 x = \frac{e ^{4}}{9} : x = - \frac{e ^{4} - 45}{18}

x = - \frac{e ^{4} - 45}{18}

Verify Solutions:

x = - \frac{e ^{4} - 45}{18}

True

The solution is

x = - \frac{e ^{4} - 45}{18}

ln (t) = 1.75

y, ln (2 y - 5) = x^{3} + a

lo g_{3} (x) - lo g_{3} (2 x - 1) = 2

lo g_{3} (x) - lo g_{3} (2 x - 1) = 0

5 ln (3 x) - 2 ln (2 x) = 6

What is the answer to ln(5-2x)+ln(9)=4 ?
The answer to ln(5-2x)+ln(9)=4 is x=-(e^4-45)/(18)
Solve for x: ln(5-2x)+ln(9)=4
The solution is x=-(e^4-45)/(18)