What is the answer to log_{3}(x)-log_{3}(2x-1)=0 ?

The answer to log_{3}(x)-log_{3}(2x-1)=0 is x=1

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log_{3}(x)-log_{3}(2x-1)=0

lo g_{3} (x) - lo g_{3} (2 x - 1) = 0

x = 1

Solution steps

lo g_{3} (x) - lo g_{3} (2 x - 1) = 0

Add

lo g_{3} (2 x - 1)

to both sides

lo g_{3} (x) - lo g_{3} (2 x - 1) + lo g_{3} (2 x - 1) = 0 + lo g_{3} (2 x - 1)

Simplify

lo g_{3} (x) = lo g_{3} (2 x - 1)

Apply log rules

x = 2 x - 1

Solve

x = 2 x - 1 : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

5 ln (3 x) - 2 ln (2 x) = 6

lo g_{2} (x^{2} + x) = 1

0 = ln (1 + (1 + c^{1}))

lo g_{2} (x - 2) + lo g_{2} (2 x - 1) = 0

lo g_{3} (3 x - 2) - lo g_{3} (x + 2) = 3

What is the answer to log_{3}(x)-log_{3}(2x-1)=0 ?
The answer to log_{3}(x)-log_{3}(2x-1)=0 is x=1
Solve for x: log_{3}(x)-log_{3}(2x-1)=0
The solution is x=1