What is the answer to 0=ln(1+sqrt((1+c^1))) ?

The answer to 0=ln(1+sqrt((1+c^1))) is c=-1

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0=ln(1+sqrt((1+c^1)))

0 = ln (1 + (1 + c^{1}))

c = - 1

Solution steps

0 = ln (1 + (1 + c^{1}))

Apply log rules

1 = 1 + 1 + c

Solve

1 = 1 + 1 + c : c = - 1

c = - 1

lo g_{2} (x - 2) + lo g_{2} (2 x - 1) = 0

lo g_{3} (3 x - 2) - lo g_{3} (x + 2) = 3

6 (ln (4 x) + 1) = 0

ln (5 - 2 x) = 3

2 lo g_{3} (x) = lo g_{10} (x^{2})

What is the answer to 0=ln(1+sqrt((1+c^1))) ?
The answer to 0=ln(1+sqrt((1+c^1))) is c=-1
Solve for c: 0=ln(1+sqrt((1+c^1)))
The solution is c=-1