What is the answer to log_{2}(x/(x+3))=1 ?

The answer to log_{2}(x/(x+3))=1 is x=-6

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log_{2}(x/(x+3))=1

lo g_{2} (\frac{x}{x + 3}) = 1

x = - 6

Solution steps

lo g_{2} (\frac{x}{x + 3}) = 1

Apply log rules

\frac{x}{x + 3} = 2^{1}

Multiply both sides by

x + 3

\frac{x}{x + 3} (x + 3) = 2^{1} (x + 3)

Simplify

x = 2 (x + 3)

Solve

x = 2 (x + 3) : x = - 6

x = - 6

Verify Solutions:

x = - 6

True

The solution is

x = - 6

2 lo g_{10} (3 - x) = 1 - x

lo g_{2} (4 x + 9) = 4

lo g_{2} (x) + lo g_{8} (x) = 8

lo g_{7} (7 x - 3) = lo g_{7} (5 x + 15)

ln (x - 1) + (\frac{1}{( 2 x - 2 )}) = c

What is the answer to log_{2}(x/(x+3))=1 ?
The answer to log_{2}(x/(x+3))=1 is x=-6
Solve for x: log_{2}(x/(x+3))=1
The solution is x=-6