What is the answer to log_{3}(12x-12)=2+log_{3}(x) ?

The answer to log_{3}(12x-12)=2+log_{3}(x) is x=4

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log_{3}(12x-12)=2+log_{3}(x)

lo g_{3} (12 x - 12) = 2 + lo g_{3} (x)

x = 4

Solution steps

lo g_{3} (12 x - 12) = 2 + lo g_{3} (x)

Apply log rules

12 x - 12 = 9 x

Solve

12 x - 12 = 9 x : x = 4

x = 4

Verify Solutions:

x = 4

True

The solution is

x = 4

20 = 3 lo g_{2} (1 + x)

lo g_{x + 1} (x^{2} + 2 x - 1) = 2

x, y - 2 = ln (x + e^{2})

lo g_{2} (x) - 3 lo g_{2} (x) = 6

lo g_{x} (2) = 0

What is the answer to log_{3}(12x-12)=2+log_{3}(x) ?
The answer to log_{3}(12x-12)=2+log_{3}(x) is x=4
Solve for x: log_{3}(12x-12)=2+log_{3}(x)
The solution is x=4