What is the answer to 8log_{2}(7p-5)-4=28 ?

The answer to 8log_{2}(7p-5)-4=28 is p=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8log_{2}(7p-5)-4=28

8 lo g_{2} (7 p - 5) - 4 = 28

p = 3

Solution steps

8 lo g_{2} (7 p - 5) - 4 = 28

Move

4

to the right side

8 lo g_{2} (7 p - 5) = 32

Divide both sides by

8

lo g_{2} (7 p - 5) = 4

Apply log rules

7 p - 5 = 16

Solve

7 p - 5 = 16 : p = 3

p = 3

Verify Solutions:

p = 3

True

The solution is

p = 3

3076 = - lo g_{10} (x)

- ln (x) = ln (\frac{1}{x})

e^{- 2 l n (x)} = ln (x^{- 2})

lo g_{10} (x) = 1.46

lo g_{4} (3 x - 4) = 4

What is the answer to 8log_{2}(7p-5)-4=28 ?
The answer to 8log_{2}(7p-5)-4=28 is p=3
Solve for p: 8log_{2}(7p-5)-4=28
The solution is p=3